Formation of which of the following compound confirms the unsaturation character of benzene :

Options

A. Cyclohexane is in 'boat' form
B. Gammexane
C. Triozonide
D. All the above

Explanation

To determine which compound confirms the unsaturation character of benzene, we will analyze the formation of different compounds from benzene and how they relate to the presence of double bonds.

### Step-by-Step Solution:

1. **Understanding Benzene Structure**:
- Benzene (C₆H₆) is an aromatic compound with a cyclic structure and alternating double bonds. This structure indicates the presence of unsaturation (double bonds).

2. **Hydrogenation to Cyclohexane**:
- When benzene undergoes hydrogenation (addition of hydrogen) in the presence of a catalyst, it converts to cyclohexane (C₆H₁₂).
- The reaction involves breaking the double bonds in benzene, confirming the unsaturation character since the double bonds are lost in the process.

3. **Excessive Chlorination to Form Gamaxane**:
- In the case of excessive chlorination of benzene, the reaction introduces chlorine atoms across the double bonds, leading to the formation of a chlorinated compound (like gamaxane).
- This reaction also results in the loss of unsaturation, as the double bonds are replaced by single bonds with chlorine.

4. **Ozonolysis to Form Glyoxal**:
- When benzene is treated with ozone (ozonolysis), followed by reduction (using H₂O₂), it results in the formation of glyoxal (C₂H₂O₂).
- This reaction breaks the double bonds and replaces them with oxygen atoms, thus confirming the loss of unsaturation.

5. **Conclusion**:
- All three reactions (hydrogenation, excessive chlorination, and ozonolysis) lead to the loss of unsaturation in benzene, confirming its unsaturation character.
- Therefore, the formation of any of these compounds (cyclohexane, gamaxane, or glyoxal) confirms the unsaturation character of benzene.

### Final Answer:
The formation of cyclohexane, gamaxane, or glyoxal confirms the unsaturation character of benzene. Thus, the correct choice is **option D** (all of the above).

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