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Statement-I : In nitration H(2)SO(4) is ...

Statement-I : In nitration `H_(2)SO_(4)` is used as sulphonating agent.
Because
Statement-II : Benzene has multicenter `pi` bonding

A

Statement-I is True, Statement-II is True : Statement-II is a correct explanation for Statement-I

B

Statement-I is True, Statement-II is True : Statement-II is `NOT` a correct explanation for Statement-I

C

Statement-I is True, Statement-II is False.

D

Statement-I is False, Statement-II is True.

Text Solution

AI Generated Solution

The correct Answer is:
**Step-by-Step Solution:** 1. **Understanding Statement-I:** - Statement-I claims that in nitration, \( H_2SO_4 \) is used as a sulphonating agent. - In reality, \( H_2SO_4 \) is not used in nitration; it is primarily used in the sulfonation reaction. 2. **Clarifying Nitration Process:** - Nitration involves the introduction of a nitro group (\( NO_2 \)) into an aromatic compound like benzene. - The nitrating mixture typically consists of concentrated nitric acid (\( HNO_3 \)) and concentrated sulfuric acid (\( H_2SO_4 \)), where \( H_2SO_4 \) acts as a catalyst to generate the electrophile \( NO_2^+ \). 3. **Conclusion on Statement-I:** - Since \( H_2SO_4 \) is not the sulphonating agent in nitration but is involved in the generation of the electrophile for nitration, Statement-I is **incorrect**. 4. **Understanding Statement-II:** - Statement-II states that benzene has multicenter \( \pi \) bonding. - Benzene is known for its resonance structure, which allows it to have delocalized \( \pi \) electrons across the six carbon atoms. 5. **Explaining Multicenter \( \pi \) Bonding:** - In benzene, the \( \pi \) electrons are not localized between two carbon atoms but are spread over all six carbon atoms, creating a stable structure. - This delocalization can be represented by various resonance forms, confirming the presence of multicenter \( \pi \) bonding. 6. **Conclusion on Statement-II:** - Since benzene indeed exhibits multicenter \( \pi \) bonding due to its resonance structures, Statement-II is **correct**. 7. **Final Evaluation:** - Statement-I is incorrect, and Statement-II is correct. Thus, the overall conclusion is that the statements are not both true. **Final Answer:** - Statement-I is false, and Statement-II is true. ---
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ALLEN-ALKENE, ALKANE & ALKYNE -EXERCISE-3
  1. Hydrocarbon (A) C(6)H(10) on treatment with H(2),Ni, H(2)//Lindlar's c...

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  2. Hydrocarbon (A) C(6)H(10) on treatment with H(2)/Ni, H(2)//Lindlar's c...

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  3. Statement-I : In nitration H(2)SO(4) is used as sulphonating agent. ...

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  4. A : C(2)H(5) -""^(+)CH —C(2)H(5) . is more stable than CH(3)-""^(+)CH-...

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  5. Assertion : Tropylium cation is aromatic in nature Reason : The only...

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  6. Assertion : Benzene on heating with conc. H(2)SO(4) gives benzenesulph...

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  7. Statement-I : Chlorination of ethyl benzene with Cl(2) in presence of ...

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  8. Statement-I : Nitration of toluene is easier than benzene Because ...

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  9. Assertion (A) Friedel - Crafts reaction benzene with n - propyl chlori...

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  10. Statement-II : Most o-,P-directing substitution are deactivating. Be...

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  11. Statement-I : Nitrobenzene does not undergo Friedel-Craft's reaction. ...

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  12. Deuterium is an isotope of hydrogen.

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  13. The typical reaction of benzene and other aromatic compounds are elect...

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  14. The typical reaction of benzene and other aromatic compounds are elect...

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  15. The typical reaction of benzene and other aromatic compounds are elect...

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  16. It is not always easy to predict the position of attack on multiply su...

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  17. It is not always easy to predict the position of attack on multiply su...

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  18. It is not always easy to predict the position of attack on multiply su...

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  19. A third group is least likely to enter between two groups in the meta ...

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  20. A third group is least likely to enter between two groups in the meta ...

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