`C_(6)H_(4)(NO_(2))CH_(3)` can form different isomers. Write three isomers.
(i) ......... (ii) ....... (iii) .......

Answer

To determine the isomers of the compound with the molecular formula C₆H₄(NO₂)CH₃, we need to consider the positions of the nitro (NO₂) group and the methyl (CH₃) group on the benzene ring. The compound can exist in different structural forms, which are known as isomers.

### Step-by-step solution:

1. **Identify the structure**: The compound has a benzene ring with one methyl group (CH₃) and one nitro group (NO₂) attached to it. The molecular formula indicates that we have a total of six carbon atoms in the ring.

2. **Determine possible positions for the substituents**: The nitro group and the methyl group can be attached to the benzene ring at different positions. The positions are classified as:
- Ortho (1,2-)
- Meta (1,3-)
- Para (1,4-)

3. **Draw the isomers**:
- **(i) Ortho isomer (2-nitro-1-methylbenzene)**: The NO₂ group is attached to the first carbon of the benzene ring, and the CH₃ group is attached to the second carbon.
- **(ii) Meta isomer (3-nitro-1-methylbenzene)**: The NO₂ group is attached to the first carbon, and the CH₃ group is attached to the third carbon.
- **(iii) Para isomer (4-nitro-1-methylbenzene)**: The NO₂ group is attached to the first carbon, and the CH₃ group is attached to the fourth carbon.

### Summary of isomers:
(i) Ortho isomer: 2-nitro-1-methylbenzene
(ii) Meta isomer: 3-nitro-1-methylbenzene
(iii) Para isomer: 4-nitro-1-methylbenzene