`CH_(3)CH_(2)-NH_(2)overset(NaNO_(2)+HCl)rarr`? The product is

Explanation

To solve the question regarding the reaction of ethylamine (CH₃CH₂NH₂) with NaNO₂ and HCl, we will follow these steps:

### Step 1: Identify the Reactants
The reactant given is ethylamine (CH₃CH₂NH₂), which is a primary amine. The reagents used are sodium nitrite (NaNO₂) and hydrochloric acid (HCl).

### Step 2: Formation of Nitrous Acid
When sodium nitrite (NaNO₂) is mixed with hydrochloric acid (HCl), nitrous acid (HNO₂) is formed in situ:
\[ \text{NaNO}_2 + \text{HCl} \rightarrow \text{HNO}_2 + \text{NaCl} \]
...