Consider the following reaction.
`CH_(3)overset(O^(16))overset(||)C-O^(18)-C_(2)H_(5)+H_(2)O^(16)underset("Heat")overset(H^(+))rarr`
The products formed in the reaction are

Options

A. `CH_(3)-overset(O^(16))overset(||)C-O^(16)=H` and `C_(2)H_(5)O^(18)H`
B. `CH_(3)-overset(O^(16))overset(||)C-O^(18)-H` and `C_(2)H_(5)O^(16)H`
C. `CH_(3)-overset(O^(16))overset(||)-O^(16)H` and `C_(2)H_(5)O^(16)H`
D. `CH_(3)-overset(O^(18))overset(||)C-O^(18)-H` and `C_(2)H^(5)O^(18)H`

Answer

To solve the given reaction, we need to analyze the reactants and the mechanism involved in the reaction step by step.

### Step 1: Identify the Reactants
The reactants in the reaction are:
- `CH3C=O` (which is an aldehyde or ketone depending on the structure)
- `O^(18)` (an isotope of oxygen)
- `C2H5` (ethyl group)
- `H2O^(16)` (water with oxygen-16)

### Step 2: Understand the Reaction Mechanism
The reaction involves the addition of water to the carbonyl group (C=O) of the aldehyde or ketone. The oxygen in water has lone pairs that can act as a nucleophile.

### Step 3: Nucleophilic Attack
The oxygen atom from water (O^(16)) will donate its lone pair to the electrophilic carbon atom of the carbonyl group (C=O). This results in the formation of a tetrahedral intermediate.

### Step 4: Formation of the Tetrahedral Intermediate
When the nucleophilic attack occurs, the double bond between carbon and oxygen breaks, leading to the following structure:
- `CH3C(OH)(O^(18)C2H5)`

### Step 5: Proton Transfer and Rearrangement
In the next step, a proton (H+) will be transferred to stabilize the intermediate. The oxygen atom that was part of the water molecule will now be bonded to the ethyl group (C2H5) and will carry the O^(18) isotope.

### Step 6: Final Products
After the rearrangement and stabilization, the final products formed from the reaction will be:
1. An alcohol: `C2H5O^(18)H` (ethanol with O^(18))
2. A carbonyl compound: `CH3C(=O)O^(16)H` (aldehyde or ketone with O^(16))

### Summary of Products
The products formed in the reaction are:
- Ethanol with O^(18): `C2H5O^(18)H`
- Aldehyde/Ketone with O^(16): `CH3C(=O)O^(16)H`