The final product in the reaction is :
`Ph-OH+C Cl_(4)overset(KOH)rarr` product

Options

A. Salicyl aldehyde
B. Salicylic acid
C. Methyl salicylate
D. benzyl chloride

Answer

To solve the reaction of phenol with CCl₄ in the presence of KOH, we will follow these steps:

### Step-by-step Solution:

1. **Identify the Reactants**: The reactants in this reaction are phenol (Ph-OH) and carbon tetrachloride (CCl₄) in the presence of potassium hydroxide (KOH).

2. **Reaction Conditions**: The reaction is carried out at a temperature of 340 Kelvin. This temperature is important as it influences the reaction pathway.

3. **Formation of Phenoxide Ion**: When phenol reacts with KOH, it forms a phenoxide ion (Ph-O⁻) and water. The reaction can be represented as:
\[ \text{Ph-OH} + \text{KOH} \rightarrow \text{Ph-O}^- \text{K}^+ + \text{H}_2\text{O} \]

4. **Formation of Alkyl Halide**: The presence of CCl₄ suggests that we can form a chlorinated compound. The phenoxide ion can react with CCl₄ to form a chlorinated derivative. The reaction can be represented as:
\[ \text{Ph-O}^- + \text{CCl}_4 \rightarrow \text{Ph-O-CCl}_3 + \text{Cl}^- \]

5. **Formation of Salicylate**: The next step involves the hydrolysis of the chlorinated product. The chlorinated compound reacts with KOH to replace the chlorine with a hydroxyl group, leading to the formation of a salicylate:
\[ \text{Ph-O-CCl}_3 + 3 \text{KOH} \rightarrow \text{Ph-O-K} + 3 \text{KCl} \]

6. **Formation of Salicylic Acid**: The final step involves the removal of water from the salicylate to yield salicylic acid (2-hydroxybenzoic acid):
\[ \text{Ph-O-K} + \text{H}_2\text{O} \rightarrow \text{Ph-OH} + \text{KOH} \]
This leads to the formation of salicylic acid:
\[ \text{Ph-OH} + \text{COOH} \rightarrow \text{C}_6\text{H}_4(\text{OH})(\text{COOH}) \]

7. **Final Product**: The final product of the reaction is salicylic acid (2-hydroxybenzoic acid), which can be represented as:
\[ \text{C}_7\text{H}_6\text{O}_3 \]

### Final Answer:
The final product in the reaction is **salicylic acid (2-hydroxybenzoic acid)**.

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