`H_(3)C-overset(O)overset(||)(C)-CH_(2)CH_(2)CO_(2)CH_(3) to H_(3)C-overset(OH)overset(||)(CH)-CH_(2)CH_(2)CH_(2)OH`
can be effected using:

Options

A. `LiAlH_(4)` and then `H^(+)`
B. `NaBH_(4)` and then `H^(+)`
C. `H_(2)//` carbon
D. None of these

Answer

To convert the compound \( H_3C-CO-CH_2CH_2CO_2CH_3 \) (which contains a ketone and an ester) to \( H_3C-CHOH-CH_2CH_2CH_2OH \) (which contains two alcohol groups), we can follow these steps:

### Step-by-Step Solution:

1. **Identify Functional Groups**:
- The starting compound has a ketone group (C=O) and an ester group (C=O with an -O-alkyl group). The target compound has two alcohol (-OH) groups.

2. **Choose a Reducing Agent**:
- To convert both the ketone and the ester into alcohols, we need a strong reducing agent. The most suitable reagent for this transformation is **Lithium Aluminum Hydride (LiAlH_4)**.

3. **Reduction Reaction**:
- When we treat the starting compound with LiAlH_4, it will reduce the ketone group to a secondary alcohol and the ester group to a primary alcohol. The reaction can be summarized as follows:
\[ \text{Ketone} \rightarrow \text{Secondary Alcohol} \]
\[ \text{Ester} \rightarrow \text{Primary Alcohol} \]

4. **Protonation**:
- After the reduction step, we need to protonate the resulting alkoxide intermediates to form the alcohols. This is typically done by adding a dilute acid (like \( H^+ \)) after the reduction.

5. **Final Structure**:
- After the reduction and protonation, the final structure will be \( H_3C-CHOH-CH_2CH_2CH_2OH \), which is the desired product.

### Summary of Steps:
- **Step 1**: Identify functional groups (ketone and ester).
- **Step 2**: Use Lithium Aluminum Hydride (LiAlH_4) as the reducing agent.
- **Step 3**: Reduce the ketone and ester to alcohols.
- **Step 4**: Protonate the alkoxide intermediates with \( H^+ \).
- **Step 5**: Confirm the final product structure.