When pinacol is treated with dilute `H_(2)SO_(4)`, a re-arangement reaction takes place which leads to the formation of a ketone.
`CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))underset(|)overset(OH)C-CH_(3)overset(H_(2)SO_(4))rarrCH_(3)-underset(CH_(3))underset(|)overset(O)overset(||)C-overset(CH_(3))overset(|)C-CH_(5)`
This reaction involves re-arrangement of carbocation
Step 1:

`CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))overset(+)overset(OH_(2))overset(|)C-CH_(2)rarrCH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))underset(|)overset(+)C-CH_(3)`
Step 2:
Carbocation rearrange by hydride, alkyl shift to get as stable as they can. Stability is the driving force for re-arrangement migration of bond may also oC Cur. Where by ring expansion and ring contraction takes place. The relief of strain can provide a powerful driving force for re-arrangement.


What will be the product of following reaction
`CH_(3)-underset(H)underset(|)overset(OH)overset(|)C-underset(H)underset(|)overset(OH)overset(|)CH_(3)overset(H_(2)SO_(4))rarrQ`
Q is:

Options

A. `CH_(3)-underset(O)underset(||)C-CH_(2)-CH_(3)`
B. `CH_(3)-underset(OH)underset(|)C=CH-CH_(3)`
C. Both
D. None

Answer

A