`CH_(3)CH_(2)CH_(2)OHoverset(PBr_(5))rarr(A)overset(KOH(Alc))rarr(B)overset(HBr)rarr(C)overset(NH_(3))rarr(D)`
Identify the product

Answer

To solve the question step by step, let's analyze the reactions one by one.

### Step 1: Reaction of Propanol with PBr5
The starting compound is propanol (CH₃CH₂CH₂OH). When propanol reacts with phosphorus pentabromide (PBr₅), it undergoes a substitution reaction where the hydroxyl group (-OH) is replaced by a bromine atom (Br).

**Reaction:**
\[ \text{CH}_3\text{CH}_2\text{CH}_2\text{OH} + \text{PBr}_5 \rightarrow \text{CH}_3\text{CH}_2\text{CH}_2\text{Br} + \text{POBr}_3 + \text{HBr} \]

**Product A:**
- The product formed is 1-bromopropane (CH₃CH₂CH₂Br).

### Step 2: Reaction of Product A with Alcoholic KOH
Next, the product A (1-bromopropane) reacts with alcoholic KOH. This reaction leads to an elimination reaction (dehydrohalogenation), where HBr is eliminated, resulting in the formation of an alkene.

**Reaction:**
\[ \text{CH}_3\text{CH}_2\text{CH}_2\text{Br} + \text{KOH (alc)} \rightarrow \text{CH}_3\text{CH}=\text{CH}_2 + \text{HBr} \]

**Product B:**
- The product formed is propene (CH₃CH=CH₂).

### Step 3: Reaction of Product B with HBr
Now, propene (Product B) reacts with HBr. According to Markovnikov's rule, the bromine will add to the more substituted carbon atom.

**Reaction:**
\[ \text{CH}_3\text{CH}=\text{CH}_2 + \text{HBr} \rightarrow \text{CH}_3\text{CHBrCH}_3 \]

**Product C:**
- The product formed is 2-bromopropane (CH₃CHBrCH₃).

### Step 4: Reaction of Product C with Ammonia
Finally, 2-bromopropane (Product C) reacts with ammonia (NH₃). This reaction leads to the formation of an amine through nucleophilic substitution, where the bromine is replaced by an amino group (-NH₂).

**Reaction:**
\[ \text{CH}_3\text{CHBrCH}_3 + \text{NH}_3 \rightarrow \text{CH}_3\text{CH(NH}_2)\text{CH}_3 + \text{HBr} \]

**Product D:**
- The product formed is propan-2-amine (CH₃CH(NH₂)CH₃).

### Summary of Products:
- **Product A:** 1-bromopropane (CH₃CH₂CH₂Br)
- **Product B:** Propene (CH₃CH=CH₂)
- **Product C:** 2-bromopropane (CH₃CHBrCH₃)
- **Product D:** Propan-2-amine (CH₃CH(NH₂)CH₃)

### Final Answer:
The final product D is propan-2-amine (CH₃CH(NH₂)CH₃).

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