When CH(2)=CH-COOH is reduced with LiAlH...

When `CH_(2)=CH-COOH` is reduced with `LiAlH_(4)`, the compound obtained will be

`CH_(3)-CH_(2)-CH_(2)OH`

`CH_(3)-CH_(2)-CHO`

`CH_(3)-CH_(2)-COOH`

`CH_(2)=CH-CH_(2)OH`

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ALLEN-ALKENE, ALKANE & ALKYNE -EXERCISE-5[A]

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