Which of the following reacts with water to form very stable product ?

Options

A. `CH_(3)Cl`
B. `C Cl_(4)`
C. `C Cl_(3)CHO`
D. `CH_(2)ClCH_(2)Cl`

Answer

To determine which compound reacts with water to form a very stable product, we can analyze the given options step by step.

### Step 1: Identify the Compounds
We have four compounds to consider:
1. Chloromethane
2. Carbon Tetrachloride
3. 1,2-Dichloroethane
4. Chloral (Trichloroacetyldehyde)

### Step 2: Analyze Each Compound's Reactivity with Water
- **Chloromethane (CH3Cl)**: This compound does not react significantly with water. It is a stable molecule and does not form any stable product upon reaction with water.

- **Carbon Tetrachloride (CCl4)**: This compound is also very stable and does not react with water. It is a non-polar solvent and does not form any product with water.

- **1,2-Dichloroethane (C2H4Cl2)**: Similar to the previous two compounds, 1,2-dichloroethane does not react with water to form a stable product.

- **Chloral (Trichloroacetyldehyde, CCl3CHO)**: This compound reacts with water to form chloral hydrate. The reaction can be represented as:

\[ \text{CCl}_3\text{CHO} + \text{H}_2\text{O} \rightarrow \text{CCl}_3\text{CH(OH)}_2 \]

### Step 3: Stability of the Product
Chloral hydrate is a very stable product due to the presence of intramolecular hydrogen bonding. The structure of chloral hydrate can be visualized as having a "butterfly-like" shape, which contributes to its stability.

### Conclusion
Among the four compounds, only **Chloral (Trichloroacetyldehyde)** reacts with water to form a stable product, which is chloral hydrate.

### Final Answer
The compound that reacts with water to form a very stable product is **Chloral (Trichloroacetyldehyde)**.

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