Benzaldehyde reacts with formaldehyde in the presence of alkali to form:-

Options

A. Methyl alcohol and sodium benzoate
B. Benzyl alcohol and sodium formate
C. Benzoic acid and ethanol
D. Formic acid and benzyl alcohol

Answer

To solve the question regarding the reaction of benzaldehyde with formaldehyde in the presence of alkali, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Benzaldehyde (C₆H₅CHO) and Formaldehyde (HCHO) are the two aldehydes involved in the reaction.

2. **Understand the Reaction Type**:
- The reaction between two aldehydes in the presence of a strong base (alkali) is known as the Cross Cannizzaro Reaction. This reaction occurs when there is no alpha hydrogen present in at least one of the aldehydes.

3. **Structure of Benzaldehyde and Formaldehyde**:
- Benzaldehyde: C₆H₅CHO (no alpha hydrogen)
- Formaldehyde: HCHO (has one hydrogen that can act as an alpha hydrogen)

4. **Reaction Mechanism**:
- In the presence of NaOH (a strong base), one molecule of benzaldehyde undergoes oxidation to form benzyl alcohol (C₆H₅CH₂OH), while the other molecule of formaldehyde is reduced to form sodium formate (HCOONa).

5. **Formation of Products**:
- The products formed from this reaction are:
- Benzyl alcohol (C₆H₅CH₂OH)
- Sodium formate (HCOONa)

6. **Final Answer**:
- Therefore, the products of the reaction between benzaldehyde and formaldehyde in the presence of alkali are benzyl alcohol and sodium formate.

### Conclusion:
The correct answer is **Benzyl alcohol and Sodium formate**.

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