2-Methylcyclohexanone is allowed to react with metachloroperoxobenzoic acid. The major product formed in the reaction is

Options

A.
B.
C.
D.

Answer

To solve the problem of determining the major product formed when 2-methylcyclohexanone reacts with metachloroperoxobenzoic acid, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are 2-methylcyclohexanone and metachloroperoxobenzoic acid (mCPBA).

- **2-Methylcyclohexanone** has a cyclohexane ring with a ketone group (C=O) and a methyl group (CH3) at the 2-position.
- **mCPBA** is a peracid that is commonly used for the oxidation of alkenes and ketones to form epoxides.

### Step 2: Understand the Reaction Mechanism
When 2-methylcyclohexanone reacts with mCPBA, the reaction typically involves the formation of an epoxide. The peracid donates an oxygen atom to the carbonyl carbon of the ketone, resulting in the formation of an epoxide.

### Step 3: Draw the Structure of 2-Methylcyclohexanone
The structure of 2-methylcyclohexanone can be represented as follows:

```
CH3
|
O=C
/ \
/ \
/ \
C C
/ \
C C
\ /
C-------C
```

### Step 4: Reaction with mCPBA
The reaction of the ketone with mCPBA will lead to the formation of an epoxide. The oxygen from the peracid will form a cyclic ether with the carbonyl carbon and one of the adjacent carbons.

### Step 5: Formation of the Major Product
The major product will be the epoxide formed from the reaction. The structure of the epoxide will be:

```
CH3
|
O=C
/ \
/ \
C O
/ \ /
C C-C
\ /
C-C
```

### Step 6: Final Product
After the reaction, the major product formed is 2-methyl-3-oxacyclohexane (the epoxide).

### Conclusion
The major product formed from the reaction of 2-methylcyclohexanone with metachloroperoxobenzoic acid is an epoxide.