Which of the following statement is//are false.

Options

A. Aldol condensation is given by all carbonyl compounds.
B. Acetaldehyde and acetone can be distinguished by lodoform test.
C. `LiAIH_(4)` converts ketones into secondary alcohols.
D. Methanol can be distinguished from ethanol by haloform reaction

Answer

To determine which statements are false, let's analyze each statement provided in the question step by step.

### Step 1: Analyze the first statement
**Statement:** "Aldol condensation is given by all carbonyl groups."

**Analysis:**
Aldol condensation requires at least two carbonyl compounds that have alpha hydrogens. Not all carbonyl compounds have alpha hydrogens. For example, benzaldehyde (C6H5CHO) does not have any alpha hydrogens, and therefore cannot undergo aldol condensation. Thus, this statement is **false**.

### Step 2: Analyze the second statement
**Statement:** "Acetaldehyde and acetone can be distinguished by iodoform test."

**Analysis:**
The iodoform test is positive for compounds that have a methyl ketone structure or a structure that can form a methyl ketone upon oxidation. Both acetaldehyde (CH3CHO) and acetone (CH3COCH3) can give a positive iodoform test because they both contain the necessary methyl group adjacent to the carbonyl. Therefore, they cannot be distinguished by the iodoform test. This statement is also **false**.

### Step 3: Analyze the third statement
**Statement:** "Lithium aluminium hydride converts ketone to secondary alcohol."

**Analysis:**
Lithium aluminium hydride (LiAlH4) is a strong reducing agent that can reduce ketones to secondary alcohols. For example, when acetone (a ketone) is treated with LiAlH4, it is reduced to isopropanol (a secondary alcohol). Therefore, this statement is **true**.

### Step 4: Analyze the fourth statement
**Statement:** "Methanol can be distinguished from ethanol by haloform reaction."

**Analysis:**
The haloform reaction requires the presence of a methyl ketone or compounds that can form such a structure. Methanol (CH3OH) does not have any alpha hydrogens and thus cannot undergo the haloform reaction. Ethanol (CH3CH2OH), on the other hand, can be oxidized to acetaldehyde, which can then participate in the haloform reaction. Therefore, methanol and ethanol can be distinguished by the haloform reaction. This statement is **true**.

### Conclusion
Based on the analysis, the false statements are:
1. "Aldol condensation is given by all carbonyl groups."
2. "Acetaldehyde and acetone can be distinguished by iodoform test."

Thus, the answer is that statements A and B are false.

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