End product of this conversion
`CH_(3)-overset(O)overset(||)(C)-CH_(2)-CH_(2)-CH_(2)-CO_(2)H overset(1. NaBH_(4))underset(2.H_(2)O,H^(+))to` is

Options

A.
B.
C.
D.

Explanation

To find the end product of the given conversion, we will follow these steps:

### Step 1: Identify the Starting Compound
The starting compound is a carboxylic acid with a ketone functional group:
\[ CH_3-C(=O)-CH_2-CH_2-CH_2-COOH \]

### Step 2: Reduction with NaBH4
Sodium borohydride (NaBH4) is a mild reducing agent that selectively reduces ketones to alcohols but does not affect carboxylic acids. In this case, the ketone group will be reduced to an alcohol.

The ketone group \( C(=O) \) will be converted to an alcohol \( C(OH) \):
\[ CH_3-CHOH-CH_2-CH_2-CH_2-COOH \]

### Step 3: Acidic Hydrolysis
Next, we perform acidic hydrolysis by adding water and an acid (H+). The hydroxyl group (OH) from the alcohol will be protonated to form an oxonium ion.

The structure now becomes:
\[ CH_3-C(OH^+)-CH_2-CH_2-CH_2-COOH \]

### Step 4: Formation of Carbocation
The oxonium ion can lose a water molecule, leading to the formation of a carbocation:
\[ CH_3-C^+-CH_2-CH_2-CH_2-COOH \]

### Step 5: Nucleophilic Attack
The lone pair on the oxygen of the carboxylic acid can now attack the carbocation, leading to the formation of a cyclic structure (ring formation). This results in the formation of a cyclic intermediate.

### Step 6: Final Product
After the rearrangement and loss of a proton (H+), the final product is formed. The structure of the final product will be:
\[ CH_3-C(OH)-CH_2-CH_2-CH_2-COOH \]

### Conclusion
The final product of the conversion is:
\[ CH_3-CHOH-CH_2-CH_2-CH_2-COOH \]
This corresponds to option A in the question.

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