On subjecting mesityl oxide to the iodoform reaction, one of the products is the sodium salt of an orgnic acid. Which acid is obtained?

Options

A. `(CH_(3))_(2)C=CH-CH_(2)COOH`
B. `(CH_(3))_(2)CH-COOH`
C. `(CH_(3))_(2)C=CH-COOH`
D. `(CH_(3))_(2)C=CH-CO-COOH`

Explanation

To solve the question regarding the iodoform reaction of mesityl oxide and identify the organic acid produced, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Mesityl Oxide**:
- Mesityl oxide is a ketone with the formula \( \text{C}_6\text{H}_{10}\text{O} \) and can be represented as \( \text{CH}_3\text{C}(=O)\text{C}(\text{CH}_3)=\text{CH}_2\text{CH}_3 \).

2. **Understand the Iodoform Reaction**:
- The iodoform reaction occurs with methyl ketones or compounds that can be converted into methyl ketones. In this reaction, the compound reacts with iodine (\( \text{I}_2 \)) in the presence of a base (usually sodium hydroxide, \( \text{NaOH} \)) to produce iodoform (\( \text{CHI}_3 \)) and a sodium salt of an organic acid.

3. **Reaction of Mesityl Oxide**:
- When mesityl oxide is subjected to the iodoform reaction, it will undergo halogenation and oxidation. The reaction can be summarized as:
\[ \text{CH}_3\text{C}(=O)\text{C}(\text{CH}_3)=\text{CH}_2 + \text{I}_2 + \text{NaOH} \rightarrow \text{CHI}_3 + \text{CH}_3\text{C}(=O)\text{O}^- \text{Na}^+ \]

4. **Identify the Organic Acid**:
- The sodium salt formed in the reaction is the sodium salt of acetic acid (\( \text{CH}_3\text{COO}^- \text{Na}^+ \)). This is because the iodoform reaction typically leads to the formation of acetic acid when a methyl ketone is involved.

5. **Conclusion**:
- Therefore, the organic acid obtained from the iodoform reaction of mesityl oxide is **sodium acetate** (the sodium salt of acetic acid).

### Final Answer:
The acid obtained is **sodium acetate**.