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Benzoic acid reacts with Ca(OH)(2). The ...

Benzoic acid reacts with `Ca(OH)_(2)`. The product obtained on dry distillation gives-

A

Benzophenone

B

Acetophenone

C

Benzaldehyde

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we will follow these steps: ### Step 1: Identify the Reactants The reactants in this reaction are benzoic acid (C₆H₅COOH) and calcium hydroxide (Ca(OH)₂). ### Step 2: Reaction of Benzoic Acid with Calcium Hydroxide When benzoic acid reacts with calcium hydroxide, it forms calcium benzoate and water. The reaction can be represented as follows: \[ \text{C}_6\text{H}_5\text{COOH} + \text{Ca(OH)}_2 \rightarrow \text{C}_6\text{H}_5\text{COO}^- \text{Ca}^{2+} + \text{H}_2\text{O} \] This can also be written as: \[ \text{C}_6\text{H}_5\text{COO}_2\text{Ca} \] ### Step 3: Dry Distillation of Calcium Benzoate The next step is to perform dry distillation on the calcium benzoate formed. During dry distillation, calcium benzoate decomposes to form benzophenone (C₁₄H₁₁O) along with calcium carbonate (CaCO₃) or calcium oxide (CaO) and water (H₂O). The reaction can be summarized as: \[ 2 \text{C}_6\text{H}_5\text{COO}^- \text{Ca}^{2+} \xrightarrow{\text{Dry Distillation}} \text{C}_6\text{H}_5\text{CO} - \text{C}_6\text{H}_5 + \text{CaCO}_3 \text{ or } \text{CaO} + \text{H}_2\text{O} \] ### Step 4: Identify the Product The main product formed from the dry distillation of calcium benzoate is benzophenone (C₁₄H₁₁O), which is a ketone. ### Conclusion Thus, the product obtained from the dry distillation of the calcium salt formed from benzoic acid and calcium hydroxide is benzophenone. ### Final Answer The product obtained on dry distillation is **benzophenone**. ---
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In the synthesis of sodium carbonate, the recovery of ammonia is done by treating NH_(4)Cl with Ca(OH)_(2) . The by-product obtained in this process is

Knowledge Check

  • In the synthesis of sodium carbonate, the recovery of ammonia is done by treating NH_(4)Cl with Ca(OH)_(2) . The by-product obtained in this process is

    A
    `CaCl_(2)`
    B
    `NaCl`
    C
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    D
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