Ethyl acetate on treatmemt with Hydrazine gives-

Options

A. `CH_(3)-underset(O)underset(||)C-NHNH_(2)`
B. `CH_(3)-underset(N,NH_(2))underset(||)C-OC_(2)H_(5)`
C. `CH_(3)-underset(O)underset(||)C-ONH.NH_(2)`
D. `CH_(3)-underset(O)underset(||)C-NH_(2)`

Answer

To solve the question of what ethyl acetate gives when treated with hydrazine, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Ethyl acetate has the structure: CH3C(=O)OCH2CH3.
- Hydrazine is represented as NH2NH2.

2. **Understand the Reaction**:
- Ethyl acetate is an ester, and hydrazine is a nucleophile due to the presence of lone pairs on nitrogen.
- The carbonyl carbon in ethyl acetate is electrophilic (positively charged) due to the electronegativity of oxygen.

3. **Nucleophilic Attack**:
- The nitrogen atom from hydrazine attacks the electrophilic carbon of the carbonyl group (C=O) in ethyl acetate.
- This forms a tetrahedral intermediate where the carbonyl oxygen becomes negatively charged.

4. **Formation of the Intermediate**:
- The structure of the intermediate after the nucleophilic attack can be represented as:
- CH3C(OH)(NH2)OCH2CH3.
- Here, the carbon is bonded to an -OH group (from the carbonyl oxygen) and an -NH2 group (from hydrazine).

5. **Elimination of Leaving Groups**:
- The intermediate undergoes rearrangement where the -OH group can leave as water (H2O) and one hydrogen from the nitrogen can leave as H+.
- This leads to the formation of a product where the nitrogen is now bonded to the carbon.

6. **Final Product**:
- The final product after the elimination of water and a proton is:
- CH3C(=O)NHNH2.
- This compound is known as an acyl hydrazone.

7. **Conclusion**:
- Therefore, the product formed when ethyl acetate is treated with hydrazine is an acyl hydrazone, specifically:
- CH3C(=O)NHNH2.

### Answer:
The product formed when ethyl acetate is treated with hydrazine is CH3C(=O)NHNH2.