Which of the following on reduction with `LiAlH_(4)` will give ethyl
alcohol ?

Options

A. `(CH_(3)CO)_(2)O`
B. `CH_(3)COCl`
C. `CH_(3)CONH_(2)`
D. `CH_(3)COOC_(2)H_(5)`

Answer

To determine which of the given compounds will yield ethyl alcohol (C2H5OH) upon reduction with lithium aluminium hydride (LiAlH4), we need to analyze each option step by step.

### Step-by-Step Solution:

1. **Identify the Structure of Ethyl Alcohol**:
- Ethyl alcohol is represented as CH3CH2OH.

2. **Analyze Each Compound**:
- We will examine each compound to see if its reduction with LiAlH4 leads to the formation of ethyl alcohol.

3. **Option 1: CH3COOH (Acetic Acid)**:
- When acetic acid (CH3COOH) is reduced with LiAlH4, it forms ethanol (C2H5OH) and water.
- **Reaction**: CH3COOH + LiAlH4 → CH3CH2OH + H2O
- **Conclusion**: This option will give ethyl alcohol.

4. **Option 2: CH3COCl (Acetyl Chloride)**:
- Acetyl chloride (CH3COCl) reacts with LiAlH4 to produce ethanol (C2H5OH) and hydrochloric acid (HCl).
- **Reaction**: CH3COCl + LiAlH4 → CH3CH2OH + HCl
- **Conclusion**: This option will also give ethyl alcohol.

5. **Option 3: CH3CONH2 (Acetamide)**:
- Acetamide (CH3CONH2) is a primary amide. When reduced with LiAlH4, it yields a primary amine (ethylamine).
- **Reaction**: CH3CONH2 + LiAlH4 → CH3CH2NH2 (ethylamine)
- **Conclusion**: This option does not give ethyl alcohol.

6. **Option 4: CH3COOC2H5 (Ethyl Acetate)**:
- Ethyl acetate (CH3COOC2H5) when reduced with LiAlH4 produces ethanol (C2H5OH) and another alcohol (ethanol).
- **Reaction**: CH3COOC2H5 + LiAlH4 → C2H5OH + CH3OH
- **Conclusion**: This option will also give ethyl alcohol.

7. **Final Conclusion**:
- The compounds that will yield ethyl alcohol upon reduction with LiAlH4 are:
- Option 1: CH3COOH
- Option 2: CH3COCl
- Option 4: CH3COOC2H5
- Therefore, the correct answer is options 1, 2, and 4.

### Summary of Correct Options:
- **Correct Options**: 1, 2, and 4.

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