Home
Class 12
CHEMISTRY
Thermal decomposition of a Mn compound (...

Thermal decomposition of a Mn compound (X) at 513 K results in compound Y, `MnO_(2)` and a gaseous product. `MnO_(2)` reacts with NaCl and concentrated `H_(2)SO_(4)` to give a pungent gas Z. X, Y and Z respectively, are :

A

`C_(6)H_(5)CONH_(2)`

B

`CH_(3)-(CH_(2))_(5)-CONH_(2)`

C

`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)-CH_(2)-CONH_(2)`

D

`CH_(3)-O-C_(6)H_(4)NH_(2)`

Text Solution

Verified by Experts

Since Y gives coupling reaction after diazotization, it suggest that Y can be anline or benzene ring subsitututed anline, Since Y has been obtained from Hofmann bromamide it means it has `-CONH_(2)` group with benzene ring. Hence, it is `C_(6)H_(5)CONH_(2)`. Hence (A) is the correct answer
Promotional Banner

Similar Questions

Explore conceptually related problems

Upon heating KClO_(3) in presence of catalytic amount of MnO_(2) , a gas W is formed. Excess amount of W reacts with white phosphorus to given X . The reaction of X with pure HNO_(3) gives Y and Z . Y and Z are, respectively

A metal X reacts with water to produce a highly combustible gas Y, and a solution Z. another metal P reacts with Z to give the same gas Y. X,Y,Z and P respectively are

KMnO_(4) in excess on treatment with concentrated H_(2)SO_(4) forms a compound (X) which decomposes explosively on heating forming (Y). The (X) and (Y) are respectively.

Reaction of an inorganic sulphite X with dilute H_(2)SO_4) generates compound Y . Reaction of Y with NaOH gives X . Further , the reaction of X and Y and water affords compound Z . Y and Z respectively are :

Upon heating KCIO_(3) in presence of catalytic amount of MnO_(2) , a gas W is formed. Excess amount of W reacts with white phosphours to given X . The reaction of X with pure HNO_(3) gives Y and Z . W and X are, respectively

SO_(2)(g)+Cl_(2)(g) to X overset(P_(4)) to Y+Z then X, Y and Z can be :

Xunderset("heat")toMnO_(2)+Y Y+H_(2)SO_(4)+NaCltoZ (pungent smelling gas) Identify X, Y and Z

Primary alkyl halide C_4H_9Br (X) reacts with alc. KOH to give compound (Y). (Y) reacts with HBr to give compound (Z) which is an isomer of (X). When (X) reacts with Na metal it gives compound (P). (X), (Y), (Z) and (P) are

[X]+H_(2)SO_(4) to [Y] a colourless gas with irritating smell, [Y]+K_(2)Cr_(2)O_(7)+H_(2)SO_(4) to green solution. [X] and [Y] are respectively :

B_2H_6+NH_3to Addition compound (X) overset(450 K)to Y+Z(g) In the above sequence Y and Z are respectively :