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A+CS(2)+HgCl(2) give C(2)H(5)-N=C=S. Thu...

`A+CS_(2)+HgCl_(2)` give `C_(2)H_(5)-N=C=S`. Thus compound
A is :-

A

`C_(2)H_(5)NH_(2)`

B

`C_(2)H_(5)NHC_(2)H_(5)`

C

`CH_(3)-CH=NOH`

D

`CH_(3)CH_(2)NO_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the compound A in the reaction \( A + CS_2 + HgCl_2 \rightarrow C_2H_5 - N = C = S \), we can follow these steps: ### Step 1: Identify the Reaction Type The reaction described is a part of the Hoffmann mustard oil reaction, which is typically used to test for primary amines. In this reaction, a primary amine reacts with carbon disulfide (CS2) and mercuric chloride (HgCl2) to form a thiourea derivative. **Hint:** Recognize that the reaction involves a primary amine and a specific reagent combination. ### Step 2: Write the General Reaction The general reaction for the Hoffmann mustard oil reaction can be represented as: \[ RNH_2 + CS_2 \rightarrow RNHCS + H_2S \] \[ RNHCS + HgCl_2 \rightarrow RNC=S + HgS + 2HCl \] **Hint:** Understand the transformation of the primary amine into a thiourea derivative through the reaction with CS2. ### Step 3: Analyze the Given Product The product given in the question is \( C_2H_5 - N = C = S \). This indicates that the starting amine (A) must be a primary amine that, when reacted, gives rise to an ethyl group (C2H5) attached to the nitrogen. **Hint:** Look for a primary amine that can yield an ethyl group upon reaction. ### Step 4: Identify the Structure of Compound A Since the product contains an ethyl group, we can deduce that compound A must be ethylamine, which has the structure: \[ C_2H_5NH_2 \] **Hint:** Consider the simplest primary amine that corresponds to the ethyl group. ### Step 5: Confirm the Reaction Now, we can confirm the reaction: 1. Ethylamine \( (C_2H_5NH_2) \) reacts with \( CS_2 \) to form \( C_2H_5NCS \). 2. This then reacts with \( HgCl_2 \) to yield \( C_2H_5N=C=S \) along with by-products \( HgS \) and \( 2HCl \). **Hint:** Verify that the reaction steps align with the expected products. ### Conclusion Thus, the compound A is ethylamine, represented as: \[ A = C_2H_5NH_2 \] ---
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ALLEN-ALKENE, ALKANE & ALKYNE -EXERCISE-1
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  2. Identify B, X and R respectively in the following sequence of reaction...

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  4. A+CS(2)+HgCl(2) give C(2)H(5)-N=C=S. Thus compound A is :-

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  5. The end product of the reaction, Ethyl amine overset(HNO(2))rarr(A)o...

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  6. In the reaction sequence :- Aoverset(SnCl(2)//HCl)rarrBunderset(0^(@))...

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  7. Methylamine on treatment with chloroform and ethanolic caustic alkal...

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  8. Which of the following is used as a solvent in the Friedel-Crafts re...

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  9. CH(3)CH(2)CONH(2)underset(Br(2))overset(NaOH)rarrA Aqueous solution ...

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  10. Hinsber's reagent is used to distinguish between

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  12. Which of the following amine will not respond to carbylamine reactio...

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  14. Which of the following reagent can be used to convert benzene diazoniu...

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  15. Hofmann's method to separate amines in a mixture uses the reagent:-

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  16. Which of the following compounds will dissolve in an alkali sol...

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  17. The number of resonating structures of aniline is :-

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  18. C(7)H(9)N has how many isomeric forms that contain a benzene ring

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  19. The reaction of RCONH(2) with a mixture of Br(2) and aqueous KOH gives...

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