In the reaction sequence :- `Aoverset(SnCl_(2)//HCl)rarrBunderset(0^(@))overset(NaNO_(2)//HCl)rarrCoverset(H_(2)O //Delta)rarrC_(6)H_(5)OH`, A,B and C are :-

Options

A. Benzene, nitrobenzene, aniline
B. Nitrobenzene, aniline and azo-compound
C. Nitrobenzene, benzene, amine
D. None of these

Answer

To solve the given reaction sequence and identify compounds A, B, and C, we will analyze each step of the reaction based on the reagents used.

### Step-by-Step Solution:

1. **Identify Compound A:**
The first reagent used is SnCl₂ in the presence of HCl. This reagent is known for reducing nitro groups to amines. Therefore, we can deduce that Compound A must be a nitro compound. The most common nitro compound in this context is nitrobenzene (C₆H₅NO₂).
- **A = Nitrobenzene (C₆H₅NO₂)**

2. **Identify Compound B:**
The reaction of nitrobenzene with SnCl₂ and HCl will reduce the nitro group to an amine group, resulting in the formation of aniline (C₆H₅NH₂).
- **B = Aniline (C₆H₅NH₂)**

3. **Identify Compound C:**
The next step involves the reaction of aniline with NaNO₂ and HCl at low temperatures (0°C). This reaction leads to diazotization, forming benzene diazonium chloride (C₆H₅N₂Cl).
- **C = Benzene diazonium chloride (C₆H₅N₂Cl)**

4. **Final Reaction:**
The final step involves heating the benzene diazonium chloride in the presence of water. This reaction leads to the hydrolysis of the diazonium salt, resulting in the formation of phenol (C₆H₅OH).
- **Final Product = Phenol (C₆H₅OH)**

### Summary of Compounds:
- **A = Nitrobenzene (C₆H₅NO₂)**
- **B = Aniline (C₆H₅NH₂)**
- **C = Benzene diazonium chloride (C₆H₅N₂Cl)**