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Aniline on treatment with excess of brom...

Aniline on treatment with excess of bromine water gives

A

2-bromoaniline

B

4-bromoaniline

C

2,4,6-tribromoaniline

D

2,6-dibromoaniline

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The correct Answer is:
To solve the question, "Aniline on treatment with excess of bromine water gives," we will follow these steps: ### Step 1: Understand the Structure of Aniline Aniline is an aromatic amine with the chemical formula C6H5NH2. The NH2 group (amino group) is attached to a benzene ring. ### Step 2: Identify the Reaction Type When aniline reacts with bromine water, it undergoes an electrophilic substitution reaction. The amino group (NH2) is a strong activating group for the aromatic ring, which increases the electron density of the ring. ### Step 3: Determine the Position of Substitution The NH2 group is ortho- and para-directing due to its electron-donating nature. This means that bromine will preferentially add to the ortho and para positions of the benzene ring. ### Step 4: Draw the Resonance Structures The lone pair of electrons on the nitrogen atom can delocalize into the benzene ring, enhancing the electron density at the ortho and para positions. This can be illustrated by drawing the resonance structures of aniline, showing how the lone pair contributes to the aromatic system. ### Step 5: Predict the Product When excess bromine water is added to aniline, bromination occurs at both the ortho and para positions. Since we have excess bromine, we expect multiple bromine atoms to be substituted onto the ring. ### Step 6: Identify the Final Product The final product will be 2,4,6-tribromoaniline, where three bromine atoms are substituted at the 2, 4, and 6 positions relative to the amino group on the benzene ring. ### Final Answer Thus, the product formed when aniline is treated with excess bromine water is **2,4,6-tribromoaniline**. ---
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ALLEN-ALKENE, ALKANE & ALKYNE -EXERCISE-1
  1. Lowest boiling point will be of the compound-

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  2. Identify B, X and R respectively in the following sequence of reaction...

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  3. Which product is a Schiff's base :-

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  4. A+CS(2)+HgCl(2) give C(2)H(5)-N=C=S. Thus compound A is :-

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  5. The end product of the reaction, Ethyl amine overset(HNO(2))rarr(A)o...

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  6. In the reaction sequence :- Aoverset(SnCl(2)//HCl)rarrBunderset(0^(@))...

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  7. Methylamine on treatment with chloroform and ethanolic caustic alkal...

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  8. Which of the following is used as a solvent in the Friedel-Crafts re...

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  9. CH(3)CH(2)CONH(2)underset(Br(2))overset(NaOH)rarrA Aqueous solution ...

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  10. Hinsber's reagent is used to distinguish between

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  11. Reactants of reaction -I are : CH(3)CONH(2),KOH,Br(2) Reactants of r...

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  12. Which of the following amine will not respond to carbylamine reactio...

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  13. (a) CH3 CONH2 +KOH +Br2 (b ) CH3 COOH + soda lime (c ) C...

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  14. Which of the following reagent can be used to convert benzene diazoniu...

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  15. Hofmann's method to separate amines in a mixture uses the reagent:-

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  16. Which of the following compounds will dissolve in an alkali sol...

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  17. The number of resonating structures of aniline is :-

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  18. C(7)H(9)N has how many isomeric forms that contain a benzene ring

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  19. The reaction of RCONH(2) with a mixture of Br(2) and aqueous KOH gives...

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  20. Aniline on treatment with excess of bromine water gives

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