Reaction -
Primary amine `+CHCl_(3)+KOHrarr` product, here product will be-

Options

A. Cyanide
B. Isocyanide
C. Amine
D. Alcohol

Explanation

To solve the reaction of a primary amine with chloroform (CHCl3) in the presence of alcoholic KOH, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- We have a primary amine (RNH2) and chloroform (CHCl3) in the presence of alcoholic KOH.

2. **Understand the Reaction Conditions**:
- The reaction occurs in an alcoholic medium with KOH, which is a strong base. This environment is crucial for the reaction to proceed.

3. **Mechanism of the Reaction**:
- The primary amine reacts with chloroform in the presence of KOH to form an intermediate. The KOH deprotonates the amine, making it a better nucleophile.
- The nucleophilic amine attacks the carbon atom in chloroform, leading to the formation of an isocyanide (also known as carbylamine).

4. **Formation of the Product**:
- The reaction results in the formation of an isocyanide (R-N≡C), which is characterized by its foul smell. The by-products of this reaction are potassium chloride (KCl) and water (H2O).

5. **Conclusion**:
- The final product of the reaction between a primary amine, chloroform, and alcoholic KOH is an isocyanide.

### Final Answer:
- The product formed is an isocyanide.