A circular arc of length `pi` cm. Find angle subtended by it at the centre in radian and degree.
Text Solution
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Comparing this equation with standard quadration `ax^(2)+bx+c=0`, we have `a=2, b=-1, c=-3` Now from, `x=(-b+-sqrt(b^(2)-4ac))/(2a), x=(-(-1)+-sqrt((-1)^(2)-4(2)(-3)))/(2(2))` `x=(1+-sqrt(1+24))/(4)=(1+-5)/(4)rArr x_(1)=(+6)/(4)=3/2` and `x_(2)=-1`
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