Solve for x: (i) `10x^(2)-27x+5=0` (ii) `pqx^(2)-(p^(2)+q^(2))x+pq=0`
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Let's solve the given quadratic equations step by step.
### Part (i): Solve for \( x \) in the equation \( 10x^2 - 27x + 5 = 0 \)
1. **Identify coefficients**:
- Here, \( a = 10 \), \( b = -27 \), and \( c = 5 \).
2. **Use the quadratic formula**:
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