Two forces of magnitudes 3N and 4N respectively are acting on a body. Calculate the resultant force if the angle between them is : (i) `0^(@)` (ii) `180^(@)` (iii) `90^(@)`
Two forces of magnitudes 3N and 4N respectively are acting on a body. Calculate the resultant force if the angle between them is : (i) `0^(@)` (ii) `180^(@)` (iii) `90^(@)`
A
`1`
B
`5`
C
`3`
D
`4`
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem of finding the resultant force when two forces of magnitudes 3N and 4N are acting on a body at different angles, we will use the formula for the resultant of two forces:
\[ F_{net} = \sqrt{F_1^2 + F_2^2 + 2 F_1 F_2 \cos(\theta)} \]
where:
- \( F_1 \) and \( F_2 \) are the magnitudes of the two forces,
- \( \theta \) is the angle between the two forces.
Let's calculate the resultant force for each angle.
### (i) When the angle \( \theta = 0^\circ \)
1. **Substitute the values into the formula:**
\[
F_{net} = \sqrt{3^2 + 4^2 + 2 \cdot 3 \cdot 4 \cdot \cos(0)}
\]
2. **Calculate \( \cos(0) \):**
\[
\cos(0) = 1
\]
3. **Now substitute \( \cos(0) \) into the equation:**
\[
F_{net} = \sqrt{9 + 16 + 2 \cdot 3 \cdot 4 \cdot 1}
\]
4. **Calculate the values:**
\[
F_{net} = \sqrt{9 + 16 + 24} = \sqrt{49}
\]
5. **Final calculation:**
\[
F_{net} = 7 \, \text{N}
\]
### (ii) When the angle \( \theta = 180^\circ \)
1. **Substitute the values into the formula:**
\[
F_{net} = \sqrt{3^2 + 4^2 + 2 \cdot 3 \cdot 4 \cdot \cos(180)}
\]
2. **Calculate \( \cos(180) \):**
\[
\cos(180) = -1
\]
3. **Now substitute \( \cos(180) \) into the equation:**
\[
F_{net} = \sqrt{9 + 16 + 2 \cdot 3 \cdot 4 \cdot (-1)}
\]
4. **Calculate the values:**
\[
F_{net} = \sqrt{9 + 16 - 24} = \sqrt{1}
\]
5. **Final calculation:**
\[
F_{net} = 1 \, \text{N}
\]
### (iii) When the angle \( \theta = 90^\circ \)
1. **Substitute the values into the formula:**
\[
F_{net} = \sqrt{3^2 + 4^2 + 2 \cdot 3 \cdot 4 \cdot \cos(90)}
\]
2. **Calculate \( \cos(90) \):**
\[
\cos(90) = 0
\]
3. **Now substitute \( \cos(90) \) into the equation:**
\[
F_{net} = \sqrt{9 + 16 + 2 \cdot 3 \cdot 4 \cdot 0}
\]
4. **Calculate the values:**
\[
F_{net} = \sqrt{9 + 16} = \sqrt{25}
\]
5. **Final calculation:**
\[
F_{net} = 5 \, \text{N}
\]
### Summary of Results:
- For \( \theta = 0^\circ \), \( F_{net} = 7 \, \text{N} \)
- For \( \theta = 180^\circ \), \( F_{net} = 1 \, \text{N} \)
- For \( \theta = 90^\circ \), \( F_{net} = 5 \, \text{N} \)
To solve the problem of finding the resultant force when two forces of magnitudes 3N and 4N are acting on a body at different angles, we will use the formula for the resultant of two forces:
\[ F_{net} = \sqrt{F_1^2 + F_2^2 + 2 F_1 F_2 \cos(\theta)} \]
where:
- \( F_1 \) and \( F_2 \) are the magnitudes of the two forces,
- \( \theta \) is the angle between the two forces.
...
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