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Two forces of magnitudes 3N and 4N respe...

Two forces of magnitudes 3N and 4N respectively are acting on a body. Calculate the resultant force if the angle between them is : (i) `0^(@)` (ii) `180^(@)` (iii) `90^(@)`

A

`1`

B

`5`

C

`3`

D

`4`

Text Solution

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The correct Answer is:
To solve the problem of finding the resultant force when two forces of magnitudes 3N and 4N are acting on a body at different angles, we will use the formula for the resultant of two forces: \[ F_{net} = \sqrt{F_1^2 + F_2^2 + 2 F_1 F_2 \cos(\theta)} \] where: - \( F_1 \) and \( F_2 \) are the magnitudes of the two forces, - \( \theta \) is the angle between the two forces. Let's calculate the resultant force for each angle. ### (i) When the angle \( \theta = 0^\circ \) 1. **Substitute the values into the formula:** \[ F_{net} = \sqrt{3^2 + 4^2 + 2 \cdot 3 \cdot 4 \cdot \cos(0)} \] 2. **Calculate \( \cos(0) \):** \[ \cos(0) = 1 \] 3. **Now substitute \( \cos(0) \) into the equation:** \[ F_{net} = \sqrt{9 + 16 + 2 \cdot 3 \cdot 4 \cdot 1} \] 4. **Calculate the values:** \[ F_{net} = \sqrt{9 + 16 + 24} = \sqrt{49} \] 5. **Final calculation:** \[ F_{net} = 7 \, \text{N} \] ### (ii) When the angle \( \theta = 180^\circ \) 1. **Substitute the values into the formula:** \[ F_{net} = \sqrt{3^2 + 4^2 + 2 \cdot 3 \cdot 4 \cdot \cos(180)} \] 2. **Calculate \( \cos(180) \):** \[ \cos(180) = -1 \] 3. **Now substitute \( \cos(180) \) into the equation:** \[ F_{net} = \sqrt{9 + 16 + 2 \cdot 3 \cdot 4 \cdot (-1)} \] 4. **Calculate the values:** \[ F_{net} = \sqrt{9 + 16 - 24} = \sqrt{1} \] 5. **Final calculation:** \[ F_{net} = 1 \, \text{N} \] ### (iii) When the angle \( \theta = 90^\circ \) 1. **Substitute the values into the formula:** \[ F_{net} = \sqrt{3^2 + 4^2 + 2 \cdot 3 \cdot 4 \cdot \cos(90)} \] 2. **Calculate \( \cos(90) \):** \[ \cos(90) = 0 \] 3. **Now substitute \( \cos(90) \) into the equation:** \[ F_{net} = \sqrt{9 + 16 + 2 \cdot 3 \cdot 4 \cdot 0} \] 4. **Calculate the values:** \[ F_{net} = \sqrt{9 + 16} = \sqrt{25} \] 5. **Final calculation:** \[ F_{net} = 5 \, \text{N} \] ### Summary of Results: - For \( \theta = 0^\circ \), \( F_{net} = 7 \, \text{N} \) - For \( \theta = 180^\circ \), \( F_{net} = 1 \, \text{N} \) - For \( \theta = 90^\circ \), \( F_{net} = 5 \, \text{N} \)

To solve the problem of finding the resultant force when two forces of magnitudes 3N and 4N are acting on a body at different angles, we will use the formula for the resultant of two forces: \[ F_{net} = \sqrt{F_1^2 + F_2^2 + 2 F_1 F_2 \cos(\theta)} \] where: - \( F_1 \) and \( F_2 \) are the magnitudes of the two forces, - \( \theta \) is the angle between the two forces. ...
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