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Vectors vecA, vecB and vecC are such tha...

Vectors `vecA, vecB and vecC` are such that `vecA.vecB=0 and vecA.vecC=0`. Then the vector parallel to `vecA` is

A

CA

B

AC

C

BC

D

CB

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Verified by Experts

The correct Answer is:
A
For triangle `ABC: vec(AB)+vec(BC)+vec(CA)=vec(0)`
Now `vec(AB)+vec(BC)+2vec(CA)`
`=vec(AB)+vec(BC)+vec(CA)+vec(CA)+vec(0)+vec(CA)=vec(CA)`
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