Let unit of length, time and mass be `L_(1), T_(1)` and `M_(1)` respectively. According to question `9.8 LT^(-2) =3L_(1)T_(1)^(-2)` `1/2 (272.1)(448)^(2) ML^(2)T^(-2)=100 M_(1)L_(1)^(2)T_(1)^(-2)` `(272.1)(448) MLT^(-1)=10 M_(1)L_(1)T_(1)` bu solving above equation `L_(1)=153.6 L` `=153.6 m`
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