In vector diagram shown in figure where `(vecR)` is the resultant of vectors `(vecA)` and `(vecB)`. If `R=(B)/sqrt(2)`, the value of angle `theta` is :
A
68.57 s
B
0.6857 s
C
6.857 s
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
C
By solving above equation `T_(1)=6.857 T` `=6.857 s`
Topper's Solved these Questions
BASIC MATHS
ALLEN|Exercise DATA SUFFICIENCY QUESTIONS|3 Videos
BASIC MATHS
ALLEN|Exercise Exercise-04 [A]|27 Videos
BASIC MATHS
ALLEN|Exercise Comprehension 3|3 Videos
AIIMS 2019
ALLEN|Exercise PHYSICS|40 Videos
CIRCULAR MOTION
ALLEN|Exercise EXERCISE (J-A)|6 Videos
Similar Questions
Explore conceptually related problems
In vector diagram shown in figure where (vecR) is the resultant of vectors (vecA) and (vecB) . If R= (B)/(sqrt2) , then value of angle theta is :
In vector diagram shown in figure where (vecR) is the resultant of vectors (vecA) and (vecB) . If R= (B)/(sqrt2) , then value of angle theta is :
a,b are the magnitudes of vectors veca & vecb . If vecaxxvecb=0 the value of veca.vecb is
The angle between vectors (vecA xx vecB) and (vecB xx vecA) is :
If a,b are the magnitudes of vectors veca & vecb and veca.vecb=0 the value of |vecaxxvecb| is
The angle between the vectors vecA and vecB is theta. The value of vecA(vecAxx vec B) is -
If theta is the angle between any two vectors veca and vecb , then |veca.vecb|=|veca xx vecb| when theta is equal to
The angle between the two vectors veca + vecb and veca-vecb is
vecA and vecB are two vectors and theta is the angle between them, if |vecA xx vecB|=sqrt(3)(vecA.vecB) the value of theta is:-
Find the angle between unit vector veca and vecb so that sqrt(3) veca - vecb is also a unit vector.
