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Four forces are acting on a body as shown in figure. The magnitude of resultant of the forces is

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The correct Answer is:
`3.5 s`
Vector `vec(PP)_(1)=-5hat(i)-5hat(k)` and `vec(P_(1)P_(2))=4hat(i)-3hat(k)`

Let angle between these vectors be `theta` then
`cos theta=((-5hat(i)-5hat(k)).(4hat(i)-3hat(k)))/((5sqrt(2))(5))=-1/(5sqrt(2))`
as `PM=PP_(1) sin theta`
so `PM=(5sqrt(2))(7/(5sqrt(2)))=7m`
Therefore `t=(7m)/(2m//s)=3.5 s`
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