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If vecAxxvecB=vec0 and vecBxxvecC=vec0, ...

If `vecAxxvecB=vec0` and `vecBxxvecC=vec0`, then the angle between `vecA` and `vecC` may be:

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The correct Answer is:
`45^(@)`
`:' m=k tan theta`
`:. Dm= k sec^(2) theta d theta`
`rArr (dm)/m=(k sec^(2) theta)/(k tan theta) d theta`
`rArr (dm)/m=(d theta)/(sin theta cos theta)=(2d theta)/(sin 2theta)`
`rArr %` error is minimum when `sin 2 theta`
has maximum value hence `2theta=pi/2` or `theta=45^(@)`
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