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For a body angular velocity vecomega=hat...

For a body angular velocity `vecomega=hati-2hatj+3hatk` and radius vector is `vecr=hati+hatj+hatk` then its velocity is

A

`[ML^(-1)T^(-2)]`

B

`[MLT^(-1)]`

C

`[ML^(-1)T^(-1)]`

D

`[ML^(-2)T^(-2)]`

Text Solution

Verified by Experts

The correct Answer is:
C
By Newton's formula
`eta=("dimensions of force")/("dimensions of area"xx "dimensions of velocity gradient")`
`=([MLT^(-2)])/([L^(2)][T^(-1)])=[ML^(-1)T^(-1)]`
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