Convert 1 newton (SI unit of force) into dyne (CGS unit of force)

Explanation

The dimensional equation of force is `[F]=[M^(1)L^(1)T^(-2)]`
Therefore if `n_(1),u_(1)`, and `n_(2), u_(2)` corresponds to SI `&` CGS units respectively, then
`n_(2)=n_(1)[(M_(1))/(M_(2))]^(1)[(L_(1))/(L_(2))]^(1)[(T_(1))/(T_(2))]^(-2)=1[(kg)/(g)][(m)/(cm)][(s)/(s)]^(-2)=1xx1000xx100xx1=10^(5)`
`therefore 1 "newton"=10^(5)` dyne.