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Refractive index mu is given as mu=A+B/l...

Refractive index mu is given as `mu=A+B/lambda^2,` where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

A

`600 mu C`

B

`60 muC`

C

`7 mu mu C`

D

`6 mu mu C`

Text Solution

Verified by Experts

The correct Answer is:
C
`q=in_(0) int vec(E)_(x).dvec(x)=in_(0)xx600 underset(0.1)overset(0.2)(int) (dx)/sqrt(x)=7xx10^(-12) C`
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