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One cm on the main scale of vernier call...

One cm on the main scale of vernier callipers is divided into ten equal parts. If 20 division of vernier scale coincide with 8 small divisions of the main scale. What will be the least count of callipers ?

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20 div. of varnier scale=8div. Of main scale `rArr 1V.S..D. =((8)/(20))M.S.D.=((2)/(5))M.S.D`
Least count `=1 M.S.D.-1V.S.D.=1 M.S.D.-((2)/(5))M.S.D.=9=(1-(2)/(5))M.S.D.`
`=(3)/(5)M.S.D.=(3)/(5)xx0.1cm=0.06cm (because 1M.S.D.=-(1)/(10)cm=0.1 cm)`
Note: for objective question `L.C.=M-V=((b-a)/(b))M=((20-8)/(20))((1)/(10))cm=(3)/(50) vm=0.06cm`
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