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The resistance R =V//I , where V = ( 100...

The resistance `R =V//I` , where `V = ( 100 +- 5)V and I = ( 10 +- 0.2)A`. Find the percentage error in `R`.

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`because R=(V)/(I) therefore (DeltaR)/(R)xx100=+-((DeltaV)/(V)+(DeltaI)/(I))xx100=+-[(5)/(100)+(0.2)/(10)]xx100=+-7%`
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