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If the error in the measurement of radiu...

If the error in the measurement of radius of a sphere in `5%` then the error in the determination of volume of the spahere will be

A

`2xx10^(-5) J`

B

`-2xx10^(-5) J`

C

`4xx10^(-5) J`

D

`-4xx10^(-5) J`

Text Solution

Verified by Experts

The correct Answer is:
D

Here `V_(DE)=V_(D)-V_(E)=20-(-20)=40V`
Work done`=qV_(DE)`
`=-1xx10^(-6)xx40`
`=-4xx10^(-5) J`
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