A ball is projected vertically up with a...

A ball is projected vertically up with an initial speed of `20m//s` on a planet where acceleration due to gravity is `10m//s^(2)`
(a) How long does it takes to reach the highest point?
(b) How high does it rise above the point of projection?
(c) How long wil it take for the ball to reach a point `10m` above the point of projection?

`tan^(-1)(3/2)`

`tan^(-1)(2/3)`

`tan^(-1)(1/2)`

`tan^(-1) (3/4)`

Text Solution

Verified by Experts

The correct Answer is:

From equation of trajectory `y=xtan theta [1-x/R]rArr 3=6 tan theta[1-1/4]rArrtan theta=2/3`

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