If `s=2t^(3)+3t^(2)+2t+8` then find time at which acceleration is zero.

Explanation

To find the time at which acceleration is zero for the given function \( s = 2t^3 + 3t^2 + 2t + 8 \), we will follow these steps:

### Step 1: Differentiate the position function to find velocity
The position function is given as:
\[ s = 2t^3 + 3t^2 + 2t + 8 \]
To find the velocity \( v \), we differentiate \( s \) with respect to \( t \):
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