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A man walks for some time 't' with veloc...

A man walks for some time 't' with velocity(v) due east. Then he walks for same time 't' with velocity (v) due north. The average velocity of the man is:-

A

`(2v_(0)^(2))/(g)`

B

`v_(0)^(2)/g`

C

`v_(0)^(2)/(2g)`

D

`v_(0)^(2)/(4g)`

Text Solution

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The correct Answer is:
To find the average velocity of a man who walks due east and then due north, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Directions and Velocities**: - The man walks due east with velocity \( v \) for time \( t \). - Then, he walks due north with the same velocity \( v \) for the same time \( t \). 2. **Calculate the Displacement for Each Segment**: - For the first segment (due east): \[ \text{Displacement}_1 = v \cdot t \quad \text{(in the east direction)} \] - For the second segment (due north): \[ \text{Displacement}_2 = v \cdot t \quad \text{(in the north direction)} \] 3. **Express the Displacements in Vector Form**: - The displacement vector for the eastward movement can be represented as: \[ \vec{d_1} = vt \hat{i} \] - The displacement vector for the northward movement can be represented as: \[ \vec{d_2} = vt \hat{j} \] 4. **Calculate the Total Displacement**: - The total displacement vector \( \vec{D} \) is the vector sum of the two displacements: \[ \vec{D} = \vec{d_1} + \vec{d_2} = vt \hat{i} + vt \hat{j} \] 5. **Simplify the Total Displacement**: - Factor out \( vt \): \[ \vec{D} = vt (\hat{i} + \hat{j}) \] 6. **Calculate the Magnitude of the Total Displacement**: - The magnitude of the total displacement \( D \) can be calculated using the Pythagorean theorem: \[ D = \sqrt{(vt)^2 + (vt)^2} = \sqrt{2(vt)^2} = vt\sqrt{2} \] 7. **Calculate the Total Time**: - The total time \( T \) taken for both segments is: \[ T = t + t = 2t \] 8. **Calculate the Average Velocity**: - The average velocity \( \vec{V}_{\text{avg}} \) is given by the formula: \[ \vec{V}_{\text{avg}} = \frac{\text{Total Displacement}}{\text{Total Time}} = \frac{vt\sqrt{2}}{2t} \] - Simplifying this gives: \[ \vec{V}_{\text{avg}} = \frac{v\sqrt{2}}{2} \] 9. **Final Result**: - The average velocity of the man is: \[ \vec{V}_{\text{avg}} = \frac{v}{\sqrt{2}} \quad \text{(in the direction of } \hat{i} + \hat{j}\text{)} \]

To find the average velocity of a man who walks due east and then due north, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Directions and Velocities**: - The man walks due east with velocity \( v \) for time \( t \). - Then, he walks due north with the same velocity \( v \) for the same time \( t \). ...
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