Three particles P, Q and R
are situated at point A on the circular path of radius 10m. All three particles move along different path and reach at point B shown in figure. Then the ratio of distance traversed by particle P and Q is:-

Options

A. `3/4`
B. `1/3`
C. `(3 pi) /4`
D. `pi /3`

Answer

B

Explanation

At maximum range vertical displacement `=0`
`rArr t'=(2u sin theta)/g`. So range R
`(u cos theta)((2u sin theta)/g)-1/2 a((2u sin theta)/g)^(2)`
`=(2u^(2) sin theta cos theta)/g(g/a-tan theta)`