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A train accelerates from rest at a const...

A train accelerates from rest at a constant rate a for time `t_(1)`and then it retards at the constant rate `b` for time `t_(2)` then comes to rest. Find the ratio `t_(1)`/`t_(2)`.

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The correct Answer is:
(i) A, B (ii) A, B (iii) B, A (iv) same (v) B, A, once
By observing the graph, position of A (Q) is greater than position of B (P) i.e. B lives farther than a and also the slope of x-t curve for A & B gives their velocities `v_(B) gt v_(A)`
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