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A jet airplane travelling at the speed of `500 km h^(-1)` ejects its products of combustion at the speed of `1500 km h^(-1)` relative to the jet plane. The speed of the products of combustion with respect to an observer on the ground is

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The correct Answer is:
(i) 17.1 s (ii) 293.8 m

(i)
`2.1=(32-2.9)/t, t=29/2.1 cong 14 :. 14+3.3 cong 17`
(ii) Height `=52+1/2 [32+2.9]xx14=293.8`
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A jet airplane travelling at the speed of 500 km ^(-1) ejects its products of combustion at the speed of 1500 km h^(-1) relative to the jet plane. What is the speed of the burnt gases with respect to observer on the ground ?

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ALLEN-MOTION IN A PALNE-EXERCISE-04[A]
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