A particle moves as shown in the following figure 1.104:

From the above curve the correct velocity-time graph for the interval of 4 seconds will be :

Answer

`360 km//hr, 1.28 km`

Explanation

`780=u sin theta xx6+1/2xxgxx36`
`780-180=u sin theta xx6`
using `theta=600/6=100 m//sec`
i.e. food package dropped before 10 secs
`1000=uxx10 rArr u=100 m//s`
`:. H=(gxx(16)^(2))/2=1280 m`.