A small ball is dropped from a certain height on the surface of a non-viscous liquid of density less than the density of ball. The motion of the ball is

Answer

(i) `100 m//s` (ii) 980 m (iii) 1600 m (iv) `(80hat(i)-140 hat(j))`

Explanation

`20=(0.6 v)/g+sqrt(2/gxx[((0.6v)^(2))/(2g)+800])` ...(i)
(i) By solving equation (i), we get `v=100 m//s`
(ii) Maximum height:
`=800+((0.6v)^(2))/(2g)=800+((0.6xx100)^(2))/20=980 m`
(iii) horizontal distance
=Horizontal velocity `xx`time of flight
`=100 cos 37^(@)xx20=1600m`
(iv) horizontal component
`v_(H)=u_(H)=100 cos 37^(@)=80 m//s`
`v_(v)=u_(v)-10xx20=100 sec 37^(@)-200`
`=140 m//s`
`:. v_("strike")=80hat(i)-140hat(j), |vec(v)|=sqrt(80^(2)+140^(2))`