A body is released form the top of a tower of height h meters. It takes t seconds to reach the ground. Where is the ball at the time t/2 sec ?

Answer

`a_(0)/2`

Explanation

Here `a_(B)(3T)=(a_(A))(2T) a_(A)=3/2 a_(B)`

`a_(AB)=a_(A)-a_(B)=3/2 a_(0)-a_(0)=a_(0)/2`