Home
Class 12
PHYSICS
A body X is projected upwards with a vel...

A body X is projected upwards with a velocity of `98 ms^(-1)`, after 4s, a second body Y is also projected upwards with the same initial velocity . Two bodies will meet after

Text Solution

Verified by Experts

The correct Answer is:
`((v_(1)+v_(2))^(2))/(2(a_(1)+a_(2)))`
`v_(12) = v_(1) - v_(2) = v_(1) - (-v_(2))=v_(1) + v_(2)`

`a_(12) = -a_(1) - a_(2) = -(a_(1) + a_(2))`.
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PALNE

    ALLEN|Exercise Exercise-05 [A]|11 Videos

  • MOTION IN A PALNE

    ALLEN|Exercise Exercise-05[B]|5 Videos

  • MOTION IN A PALNE

    ALLEN|Exercise EXERCISE-04[A]|35 Videos

  • KINEMATICS-2D

    ALLEN|Exercise Exercise (O-2)|46 Videos

  • NEWTON'S LAWS OF MOTION & FRICTION

    ALLEN|Exercise EXERCISE (JA)|4 Videos

Similar Questions

Explore conceptually related problems

A body is projected up with a velocity 50 "ms"^(-1) after one second if accelaration due to gravity disappears then body

A particle is projected vertically upwards and t second after another particle is projected upwards with the same initial velocity. Prove that the particles will meet after a lapse of ((t)/(2)+(u)/(g)) time from the instant of projection of the first particle.

A body is projected vertically upwards wth a velocity u=5m//s . After time t another body is projected vertically upward from the same point with a velocity v=3m//s . If they meet in minimum time duration measured from the projection of first body, then t=k/g sec find k (where g is gravitatio acceleration).

A body is projected with a velocity 60 ms ^(-1) at 30^(@) to horizontal . Its initial velocity vector is

A body is projected with a velocity 50 "ms"^(-1) . Distance travelled in 6th second is [g=10 ms^(-2)]

A body is projected with an initial elocity 20m/s at 60° to the horizontal. The displacement after 2 s is

A body is projected upwards with a velocity of 4 xx 11.2 "km s"^(-1) from the surface of earth.What will be the velocity of the body when it escapes from the gravitational pull of earth ?

A body is thrown up with a velocity 29.23 "ms"^(-1) distance travelled in last second of upward motion is

If a body is projected with a speed lesser than escape velocity, then

A body is projected vertically up with velocity 98 "ms"^(-1) . After 2 s if the acceleration due to gravity of earth disappears, the velocity of the body at the end of next 3 s is