The position `x` of a particle varies with time `t` as `x=at^(2)-bt^(3)`. The acceleration at time `t` of the particle will be equal to zero, where (t) is equal to .`
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The correct Answer is:
5
As observed from A, B moves perpendicular to line of motion of A. It means velocity of b along A is equal to velocity of a `V_(B) cos 30=100sqrt(3)` `V_(B)=200` If a is observer a remains stationary therefore `t=500/(V_(B) sin 30)=500/100=5`
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