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A body is projected up such that its pos...

A body is projected up such that its position vector varies with time as `r = { 3thati + (4 t - 5t^2)hatj}` m. Here, t is in seconds. Find the time and x-coordinate of particle when its y-coordinate is zero.

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y co-ordinate of particle `=4t-5t^(2)=0rArrt=(4)/(5)s=40.8s`
At that time `x=3xx(4)/(6)=(12)/(5)m=2.4m`
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